PHP preg_replace to replace content within specific tags

Question

I want to change this:

<div>
  <div>
    <div id="myList">
      <table><tr><td></td></tr></table>
    </div>
  </div>
</div>

Into this:

<table><tr><td></td></tr></table>

What would the preg_replace() be? I have tried the following but to no avail:

$result = preg_replace('#<div(.*?)(?! id="myList")>(.*?)</div>#is', '', $result);

Mihai Matei · Accepted Answer · 2016-10-07 11:45:33Z

4

You can use strip_tags

$string = '<div>
  <div>
    <div id="myList">
      <table><tr><td></td></tr></table>
    </div>
  </div>
</div>';

echo strip_tags($string, '<table><tr><td>');

answered Oct 7, 2016 at 11:45

Mihai Matei

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1 Comment

Machavity Over a year ago

Props to you for avoiding the RegEx pony

mhmd · Accepted Answer · 2016-10-07 12:03:54Z

1

@Reado try this

$s='<div>
  <div>
    <div id="myList">
      <table><tr><td></td></tr></table>
    </div>
  </div>
</div>';
    $replace=str_replace(array('<div>', '<div id="myList">','</div>'),"",$s);

answered Oct 7, 2016 at 12:03

mhmd

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