Swift Convert string Base64 to UIImage

Question

I'm trying to convert base 64 encoded string to UIImage with the following code:

let decodedData = NSData(base64EncodedString: base64String!, options: NSDataBase64DecodingOptions(rawValue: 0) )

print(decodedData) //I get data here (It is not nil)

var decodedimage = UIImage(data: decodedData!) //return nil

The decodedData seems fine, Why do I get nil when converting to UIImage?

If decodedData != nil but decodedimage == nil then the data is not in a valid image format. — Martin R
– Martin R, Commented Oct 9, 2016 at 12:28
Hi, you right! It was extra characters at the beginning of the base64 string. Thanks! — Eyal
– Eyal, Commented Oct 10, 2016 at 6:09

Damien · Accepted Answer · 2016-10-09 12:18:17Z

7

Try to pass no options, I also recommend using unwrap for optionals :

if let string = base64String {
    let decodedData = NSData(base64EncodedString: base64String!, options: []) 
    if let data = decodedData {
        var decodedimage = UIImage(data: data)
    } else {
        print("error with decodedData")
    }
} else {
    print("error with base64String")
}

answered Oct 9, 2016 at 12:18

Damien

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4 Comments

Eyal Over a year ago

Hi, Thanks, I will try it.

Eyal Over a year ago

Hi, unfortunately it didn't solve my problem. The program doesn't print any of 2 prints in code. It means that the data is not nil. For some reason, the code refuse to convert the 'data' to UIImage and return nil in that step.

Damien Over a year ago

could be a problem with the data you retrieve

Eyal Over a year ago

Yes, you right. As I mentioned above, I got several characters at the beginning of the Base64 string. After I removed it, the data could be converted to UIImage.

ssowri1 · Accepted Answer · 2019-03-06 13:38:59Z

1

For Swift 4.2

if base64String != nil {
        let decodedData = NSData(base64Encoded: base64String!, options: [])
        if let data = decodedData {
            let decodedimage = UIImage(data: data as Data)
            cell.logo.image = decodedimage
        } else {
            print("error with decodedData")
        }
    } else {
        print("error with base64String")
    }

answered Mar 6, 2019 at 13:38

ssowri1

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