How to suppress errors in shelljs?

Question

When I run the following code in node:

var shell = require('shelljs');
var files = shell.ls('-R', './**/foobar');
console.log('Files found:\n' + files.join('\n'));

I see this in the output:

ls: no such file or directory: ./**/foobar

How can I suppress the stderr, keep it from being shown?

Douglas Ludlow · Accepted Answer · 2016-10-20 16:36:16Z

7

Took me a bit to figure this out, but you need to configure shelljs to be silent, like so:

var shell = require('shelljs');
shell.config.silent = true;

From the README, this:

Suppresses all command output if true, except for echo() calls. Default is false.

answered Oct 20, 2016 at 16:36

Douglas Ludlow

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1 Comment

Thanks, this works. Passing {silent: true} to exec() doesn't seem to be enough.