If statement not triggering

Question

I am trying to make this code alternate between setting i as 56 and i as 0 I cant seem to get the second if statement to trigger. The first one works.

  while True:
        print 'is55 before if logic is' + str(is56)
        if is56 == True:
            i = 0 
            is56 = False 
            #print 'true statement' + str(i)
            print 'True is56 statement boolean is ' + str(is56)
        if is56 == False:   
            i = 56 
            is56 = True                
        print  'i is ' + str(i)

This code is not complete, please post a minimal reproducible example — ForceBru
– ForceBru, Commented Oct 24, 2016 at 18:12

Mureinik · Accepted Answer · 2016-10-24 18:13:00Z

2

You have two separate if, so you enter the first one, set is56 to False, and then immediately enter the second one and set it back to True. Instead, you could use an else clause:

while True:
    print 'is55 before if logic is' + str(is56)
    if is56:
        i = 0 
        is56 = False 
    else: # Here!
        i = 56 
        is56 = True                
    print  'i is ' + str(i)

answered Oct 24, 2016 at 18:13

Mureinik

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Comments

Ari Gold · Accepted Answer · 2016-10-24 18:38:30Z

1

any objections ?

while True:
    print 'is55 before if logic is' + str(is56)
    i = is56 = 0 if is56 else 56             
    print  'i is ' + str(i)

answered Oct 24, 2016 at 18:38

Ari Gold

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Comments

Moses Koledoye · Accepted Answer · 2016-10-24 18:25:38Z

0

The changes in the first if block are immediately reversed by the next one.

You want to replace the separate if blocks with a single if/else block.

On another note, you could simply use an itertools.cycle object to implement this:

from itertools import cycle

c = cycle([0, 56])

while True:
    i = next(c)
    print  'i is ' + str(i)
    # some code

edited Oct 24, 2016 at 18:25

answered Oct 24, 2016 at 18:14

Moses Koledoye

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Comments

alexanderbird · Accepted Answer · 2016-10-24 19:02:34Z

0

Without an elif, the original code, if working, would execute both blocks. Why not:

def print_i(i):
    print 'i is ' + str(i)

while True: 
    print_i(56)
    print_i(0)

answered Oct 24, 2016 at 19:02

alexanderbird

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