Python if statement not functioning

Question

print("Hello World")
myName = input("What is your name?")
myVar = input("Enter a number:")
if myName == "MZ" or myVar != 0:
    print("MZ is great")
elif myName == "MV":
    print("MV is ok")
else:
    print("Hello World")

No matter what I input as name myName or number myVar, it always prints MZ is great.

Please help. Thanks

No, probably a string. Because that's what input() returns. And since the comparison is (in)equality, no exception is raised. — Ignacio Vazquez-Abrams
– Ignacio Vazquez-Abrams, Commented Apr 28, 2017 at 0:31
Parentheses are not necessary on the if statement, by the way — OneCricketeer
– OneCricketeer, Commented Apr 28, 2017 at 0:37

kichik · Accepted Answer · 2017-04-28 00:32:21Z

4

First off, MZ is great!

This happens because of or myVar != 0. Since input() returns a string (in Python 3) and you compare it to a number, myVar will never be equal to the number 0. You should do something like:

myVar = int(input("Enter a number:"))

You should probably also catch ValueError in case the user types a bad number.

answered Apr 28, 2017 at 0:32

kichik

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1 Comment

user339054 Over a year ago

Thankyou Allen and kichik. Tried both solutions and both work fine. MZ is great! :)

Allen Qin · Accepted Answer · 2017-04-28 00:31:55Z

3

Change

if(myName == "MZ" or myVar != 0)

to

if(myName == "MZ" or myVar != "0")

User input is string by default.

answered Apr 28, 2017 at 0:31

Allen Qin

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1 Comment

user339054 Over a year ago

Thankyou Allen and kichik. Tried both solutions and both work fine. MZ is great! :)

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