How to calculate difference of two string dates in days using PHP?

Question

I have two date variables:

$dnow = "2016-12-1";
$dafter = "2016-12-11";

I want to calculate the difference of this two dates which are in string format so how do I calculate? I used

date_diff($object, $object2)

but it expecting two date object, and I have dates in String format , After using date_diff I get following error

Message: Object of class DateInterval could not be converted to string.

Possible duplicate of How to calculate the difference between two dates using PHP? — Rav
– Rav, Commented Dec 1, 2016 at 8:09
Possible duplicate of Finding the number of days between two dates — Mohammad
– Mohammad, Commented Dec 1, 2016 at 8:13

score 7 · Accepted Answer · 2016-12-01 09:02:38Z

7

Try this, use date_create

$dnow = "2016-12-1";
$dafter = "2016-12-11";
$date1=date_create($dnow);
$date2=date_create($dafter);
$diff=date_diff($date1,$date2);
print_r($diff);

DEMO

edited Dec 1, 2016 at 9:02

answered Dec 1, 2016 at 8:38

user7234690

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Comments

Jerodev · Accepted Answer · 2016-12-01 09:37:33Z

6

You could use the strtotime function to create a timestamp of both dates and compare those values.

<?php

$start = strtotime('2016-12-1');
$end = strtotime('2016-12-11');
$diffInSeconds = $end - $start;
$diffInDays = $diffInSeconds / 86400;

edited Dec 1, 2016 at 9:37

answered Dec 1, 2016 at 8:24

Jerodev

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2 Comments

Mohammad Over a year ago

The code return difference time in second. You should convert it to day.

Jerodev Over a year ago

There are 86400 seconds in a day, so divide the result by this number.

Mohammad · Accepted Answer · 2016-12-01 08:35:49Z

3

$datetime1=date_create($dnow);
$datetime2 = date_create($dafter);
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
//%R is used to show +ive or -ive symbol and %a is used to show you numeric difference

edited Dec 1, 2016 at 8:35

Mohammad

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answered Dec 1, 2016 at 8:29

Aditya

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Comments

Pikamander2 · Accepted Answer · 2021-11-19 09:29:42Z

0

If you just need the number of days, then you can use the DateInterval object's days property.

$day1 = '2016-12-1';
$day2 = '2016-12-11';
$days_elapsed = date_diff(date_create(date($day1)), date_create($day2)) -> days;

echo $days_elapsed; //Outputs 10

answered Nov 19, 2021 at 9:29

Pikamander2

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Comments

score -1 · Accepted Answer · 2016-12-01 09:19:18Z

-1

$dnow = "2016-12-1";
$dafter = "2016-12-11";
$dnow=date_create($dnow);
$dafter=date_create($dafter);
$difference=date_diff($dnow,$dafter);

edited Dec 1, 2016 at 9:19

answered Dec 1, 2016 at 9:03

user6623857

2 Comments

Mohammad Over a year ago

Duplicate of @krunal answer.

Mohammad Over a year ago

You only changed variable name, but solution is same.

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