Here is the behaviour I'm looking for:
function one(func){
func(5);
}
function two(arg1, arg2){
console.log(arg1);
console.log(arg2);
}
one(two(3)) //prints 3, 5
Can this behaviour or something similar be accomplished in javascript?
7 Answers
You can always use the bind() function to pass some arguments to your function. It'll create a new function with the first argument - arg1 - equal to the value of 3 in this example:
function one(func){
func(5);
}
function two(arg1, arg2){
console.log(arg1);
console.log(arg2);
}
one(two.bind(null, 3))
You can read more about the bind() function here: MDN - Bind
Comments
Some workaround is possible
function one() {
var args = Array.prototype.slice.call(arguments);
var func = args[0];
args.splice(0, 1);
args.push(5);
func.apply(this, args);
}
function two(arg1, arg2) {
console.log(arg1);
console.log(arg2);
}
one(two, 3)
Comments
There's a problem with your syntax: function one is expecting its single argument to be a function. Then, below, when you invoke it, you are not passing the function two, but whatever two returns when it's passed a single argument, probably undefined. I don't know what specifically you're trying to accomplish but I'd recommend a little research into closures.
1 Comment
devellopah
if
two(3) call returns a function then one is receiving function as argument.function one(arg){
two(arg, 5); // func here is two so it requires two params...
}
function two(arg1, arg2){
console.log(arg1);
console.log(arg2);
}
one(3)// one expect function so can't execute function here!
1 Comment
Adam Griffiths
Not really what I was looking for, the idea is the function one doesn't know what the first argument to be passed is before the function is called
as soon as one expects function as argument two(3) should return function.
this condition is required
so in order to achieve it your two function should be
function two(arg1){
console.log(arg1);
return function(arg2) {
console.log(arg2);
};
}
so two(3) function call gets passed as argument to one
so before assigning value to variable engine executes it. And execution of two(3) call logs 3 to console and returns function
function(arg2) {
console.log(arg2);
};
and then engine assigns executed value(returned function) to func variable.
so func parameter of one function now looks like
func = function(arg2) {
console.log(arg2);
};
one calls func with 5 passed in as argument.
so 5 gets logged to console.
Comments
Basically you can't specify the parameter in the function or it'll run. You need to specify the function aka one(two), but that obviously wouldn't work.
However if you dynamically create a function you should be able to accomplish the task like so :
function one(func){
func(5);
}
function two(arg1, arg2){
console.log(arg1);
console.log(arg2);
}
one(function(val) { two(3, val) }) //prints 3, 5
Comments
well somehow this things work for me
function one(func){
console.log("one is running");
func;
}
function two(args1, args2){
console.log("two is running");
console.log("args1 -> " + args1);
console.log("args2 -> " + args2);
}
//to call it
args1 = 6;
args2 = 12
one(two(args1,args2));
twoyet are immediately trying to log the value of two arguments, at least one of which cannot exist.