JavaScript How to pass a parameter to a function

Question

I am having trouble passing a parameter to a function.

Here is my code (edited to show flow and positioning in the html doc):

<!-- this src file precedes -->
    // this resides in a js src file on its own and as is
    function mySpecialFunction(thisIndex) {
      alert(thisIndex); // shows as blank
    }

<!-- this src file follows -->
$(document).ready(function() {
  $(window).load(function() {
    $(document).on('change', '.jq__pAC', function(event) {
    var i = 1;
    // some JavaScript code
    mySpecialFunction(i);
    // some more JavaScript code
    }); // end jq__pAC
  }); // end .load()
}); // end .ready()

my alert() event displays blank.

The 2 blocks of js code are in separate src files. Does that have anything to do with it?

Yeah, there's absolutely nothing wrong with that code. What browser are you using? -- I see they are in different files. Simply include the function before you include the call for it. — ndugger
– ndugger, Commented Apr 28, 2014 at 20:48
sure does @j08691 -- and even to my "eyeball" I see nothing wrong with it. — H. Ferrence
– H. Ferrence, Commented Apr 28, 2014 at 20:48
It doesn't matter if the code is in 2 different places, you just need to make sure that the file which defines the function is called first. — APAD1
– APAD1, Commented Apr 28, 2014 at 20:49

Patrick Hofman · Accepted Answer · 2014-04-28 20:58:25Z

4

If you say the functions are in different files, probably the order of the files in the problem.

Make sure that the calling method (mySpecialFunction(i);) comes after the declaration (function mySpecialFunction(thisIndex)).

EDIT:

In your edit you have $(document).ready and $(window).load. Remove the last one and it will work.

See jsfiddle.

edited Apr 28, 2014 at 20:58

answered Apr 28, 2014 at 20:48

Patrick Hofman

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12 Comments

H. Ferrence Over a year ago

is javascript not like PHP where the functions can live wherever @PatrickHofman?

Patrick Hofman Over a year ago

No. It is not. You have to declare it before you use it.

H. Ferrence Over a year ago

ok, thanks -- that's probably my problem. I'll check @PatrickHofman

ndugger Over a year ago

Not if they're in separate files, though. The function itself must be declared before the call, if they reside in separate files.

Patrick Hofman Over a year ago

@FelixKling: I didn't think so when using multiple files. In the same file it does.

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