How to get substring in scala?

Question

How do I get the substring for the string :

 "s3n://bucket/test/files/*/*"

I would like to get s3n://bucket/test/files alone. I tried the split :

"s3n://bucket/test/files/*/*".split("/*/*") but this gives me array of strings with each character.

nmat · Accepted Answer · 2017-02-09 01:20:36Z

7

The argument to split is a regex and /*/* matches all the characters in your string. You need to escape *:

"s3n://bucket/test/files/*/*".split("/\\*/\\*")

An alternative to split in this case could be:

"s3n://bucket/test/files/*/*".stripSuffix("/*/*")

answered Feb 9, 2017 at 1:00

nmat

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Comments

Brian · Accepted Answer · 2017-02-09 01:32:29Z

6

A couple of options not using a regex.

Using takeWhile gives "s3n://bucket/test/files/" which includes the last slash.

scala> s.takeWhile(_ != '*')
res11: String = s3n://bucket/test/files/

Using indexOf to find the first "*" and taking one less character than that gives the output you specify.

scala> s.slice(0,s.indexOf("*") - 1)
res14: String = s3n://bucket/test/files

answered Feb 9, 2017 at 1:32

Brian

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