Following my first question How to convert an hexadecimale line in a text file to an array (Python)?, I need to convert a numpy file containing an hexadecimal array to a binary file, My numpy array looks like this:
[['7a', '8e', '5d', 'c3', '90', '78', '1e', 'ab', '8d', 'f2', 'c0', '90', 'bf',
'4b', 'eb', 'ca'],
['db', 'ac', '0f', 'ba', '55', 'd3', 'd4', 'fc', '17', '71', '61', 'bf', 'e2',
'4d', 'c7', 'fb'],
['82', 'e5', 'a7', 'a0', '21', '19', '7f', '6f', 'be', '94', 'a8', '67', 'd4',
'bb', '38', '95'],
['85', '05', '80', 'c1', 'ff', 'ec', '88', '7c', '50', '00', 'c9', 'b3', 'a0',
'e6', 'b3', '9d'],
['15', '26', 'af', '37', 'ce', '4b', '0b', '4e', '81', 'f8', 'af', '06', '47',
'e3', '71', '19'],
['ba', 'b1', '9c', '53', 'fd', '86', 'e6', 'af', 'c9', '33', '27', '6b', '28',
'6e', '0c', '36'],
['b5', '2e', '53', '00', '7b', 'eb', 'e8', '87', '7c', 'e5', '69', 'ad', '24',
'94', 'dd', '76'],
['44', 'fd', '87', 'e9', 'b1', 'a4', '0a', '92', '9a', 'b6', '13', '56', '65',
'c2', '2d', '0f'],
['a8', '8e', '51', '41', 'dd', 'c9', '9e', '02', '07', 'a9', 'e1', '44', 'f4',
'01', '0a', '22'],
['58', 'ff', '59', '78', '19', 'ea', '0a', 'a3', '70', '24', 'a1', 'f1', 'f8',
'4c', '52', '24']]
I try by using this code:
import numpy as np
import struct
textin = np.load('/home/msmache/Bureau/OutFilePlaintexts.npy')
f = open('/home/msmache/Bureau/Plaintexts', 'wb')
for t in textin.flatten():
f.write(struct.pack('h', t))
f.close()
I found this error:
f.write(struct.pack('h', t))
error: pack expected 3 items for packing (got 1)
