tuple error array format

Question

Just started programming python. I have a question with this error IndexError: tuple index out of range. This app is somewhat reading large amount of log files.

my example list is:

arrline = ['Array0', 'Array1', 'Array2', 'Array3', 'Array4', 'Array5', 'Array6:', 'Array7', 'Array8', 'Array9', 'Array10', 'Array11', 'Array12', 'Array13', 'Array14', 'Array15', 'Array16']

when I use

tmp1 = '{0}{1}{12}{5}{6}{17}'.format(*arrline)
print tmp1

I end up getting IndexError: tuple index out of range.

but when I try

tmp1 = '{0}{1}{2}{3}{4}{5}'.format(*arrline)

It doesn't get any errors.

Any help is greatly appreciated.

{17} would need arrline to have 18 items at least.

Jean-François Fabre
– Jean-François Fabre ♦

2017-02-20 10:24:04 +00:00
Commented Feb 20, 2017 at 10:24 — Jean-François Fabre
– Jean-François Fabre ♦, Commented Feb 20, 2017 at 10:24

Anna Jeanine · Accepted Answer · 2017-02-20 10:24:14Z

2

IndexError: tuple index out of range.

This error tries to tell you that you're trying to get an object from the tuple which is not in the index range of the defined tuple. The {17} which you're trying to print doesn't exist!

But your code which request items up until {5} can be executed because of the 16 items in the tuple!

Try to add another item to your tuple, or change {17} to {16}

answered Feb 20, 2017 at 10:24

Anna Jeanine

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Piyush S. Wanare · Accepted Answer · 2017-02-20 10:36:54Z

0

Because your array contains 17 elements but according to array indexing it's 0-16, Array Index always starts from 0 so as you are using {17} , This index is not available you start counting from 0 , That's why your getting error {17} while tmp1 = '{0}{1}{12}{5}{6}{17}'.format(*arrline)'

answered Feb 20, 2017 at 10:36

Piyush S. Wanare

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