Error when returning value in C# 2.0

Question

I downloaded an example application for using some web services with an online system.

I am not sure if all code below is needed but it is what I got and what I am trying to do is to use the search function.

I start by calling searchCustomer with an ID I have:

partnerRef.internalId = searchCustomer(customerID);

And the code for searchCustomer:

private string searchCustomer(string CustomerID)
        {

            string InternalID = "";

            CustomerSearch custSearch = new CustomerSearch();
            CustomerSearchBasic custSearchBasic = new CustomerSearchBasic();

            String nameValue = CustomerID;
            SearchStringField entityId = null;

                entityId = new SearchStringField();
                entityId.@operator = SearchStringFieldOperator.contains;
                entityId.operatorSpecified = true;
                entityId.searchValue = nameValue;
                custSearchBasic.entityId = entityId;

            String statusKeysValue = "";
            SearchMultiSelectField status = null;
            if (statusKeysValue != null && !statusKeysValue.Trim().Equals(""))
            {
                status = new SearchMultiSelectField();
                status.@operator = SearchMultiSelectFieldOperator.anyOf;
                status.operatorSpecified = true;
                string[] nskeys = statusKeysValue.Split(new Char[] { ',' });

                RecordRef[] recordRefs = new RecordRef[statusKeysValue.Length];
                for (int i = 0; i < nskeys.Length; i++)
                {
                    RecordRef recordRef = new RecordRef();
                    recordRef.internalId = nskeys[i];
                    recordRefs[i] = recordRef;
                }
                status.searchValue = recordRefs;
                custSearchBasic.entityStatus = status;
            }


            custSearch.basic = custSearchBasic;

            SearchResult response = _service.search(custSearch);

            if (response.status.isSuccess)
            {

                processCustomerSearchResponse(response);




                    if (seachMoreResult.status.isSuccess)
                    {

                        processCustomerSearchResponse(seachMoreResult);

                        return InternalID;
                    }
                    else
                    {
                        _out.error(getStatusDetails(seachMoreResult.status));

                    }

            }
            else
            {
                _out.error(getStatusDetails(response.status));
            }

            return InternalID;
        }

In the code above processCustomerSearchResponse gets called

processCustomerSearchResponse(response);

The code for this function is:

public string processCustomerSearchResponse(SearchResult response)
{
    string InternalID = "";
    Customer customer;

        customer = (Customer)records[0];
        InternalID = customer.internalId;

        return InternalID;
}

What the original code did was to write some output in the console but I want to return the InternalID instead. When I debug the application InternalID in processCustomerSearchResponse contains the ID I want but I don't know how to pass it to searchCustomer so that function also returns the ID. When I debug searchCustomer InternalID is always null. I am not sure on how to edit the code under response.status.isSuccess to return the InternalID, any ideas?

Thanks in advance.

Kyle Trauberman · Accepted Answer · 2010-11-22 23:59:57Z

1

When you call processCustomerSearchResponse(response);, you need to store the return value in memory.

Try modifying your code like this:

 InternalID = processCustomerSearchResponse(response);

answered Nov 22, 2010 at 23:59

Kyle Trauberman

25.7k13 gold badges88 silver badges124 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Error when returning value in C# 2.0

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related