python list to subprocess in for loop

Question

In python if I have interfaces = netifaces.interfaces() which is a list returning: ['lo','eth0','eth1']

how to I loop over that list passing lo and eth0, eth1 into several subprocess calls to ethtool?

subprocess.call(['ethtool %'] interfaces) --- lo
subprocess.call(['ethtool %'] interfaces) --- eth0
subprocess.call(['ethtool %'] interfaces) --- eth1

I want to run ethtool for the number of items in my interfaces list but for each pass I want to substitute the next item in the interfaces list and pass that to the subprocess.call.

Any reason why you can't just put this in a for loop, as your question title states? — Shadow
– Shadow, Commented Mar 16, 2017 at 5:16
yes. I want to put it in a for loop but how to I pass in each item of the interfaces list on each pass? for interface in interfaces: subprocess.call(['ethtool %'] ????) — god
– god, Commented Mar 16, 2017 at 5:17
I see. I've added an answer. The list you are passing to call is a list of arguments. So just provide interface as the second item in the list. — Shadow
– Shadow, Commented Mar 16, 2017 at 5:22

Shadow · Accepted Answer · 2017-03-16 05:20:29Z

2

As far as I can tell, you just want to do a normal for loop...

interfaces = netifaces.interfaces()
for interface in interfaces:
    subprocess.call(["ethtool", interface])

answered Mar 16, 2017 at 5:20

Shadow

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Comments

god · Accepted Answer · 2017-03-17 17:00:42Z

0

for interface in interfaces:
    print("[+] Fetching LLDP info for ", interface)
    subprocess.call(['lldptool', '-t', '-n', '-i', interface])
    print("[+] Printing ethtool info for ", interface)
    subprocess.call(['ethtool', interface])

I turns out I was passing in the interface outside of the subprocess call and once I put it inside the [] it worked as expected. I love this site! Thank you shadow

edited Mar 17, 2017 at 17:00

answered Mar 16, 2017 at 5:32

god

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