Replace domain name string

Question

I have URLs in my string like below:

subdomain.domain.com/ups/a/b.gif
www.domain.com/ups/c/k.gif
subdomain1.domain.com/ups/l/k.docx

Looking to replace all URL like below:

anydomain.com/ups/a/b.gif
anydomain.com/ups/c/k.gif
anydomain.com/ups/l/k.docx

In above string (URL + ups) is common to match. All URLs are started with either HTTP or HTTPS.

If any of the answers were helpful you should upvote them, and mark as accepted the one answer that best answered your question. See also stackoverflow.com/help/someone-answers — miken32
– miken32, Commented Mar 24, 2017 at 5:11

miken32 · Accepted Answer · 2017-09-13 18:15:22Z

6

As suggested in comments, the way to parse URLs is with parse_url().

<?php
$urls = [
    "http://subdomain.domain.com/ups/a/b.gif",
    "https://www.example.com/ups/c/k.gif",
    "https://subdomain1.domain.com/ups/l/k.docx",
];
$domain = "anydomain.com";
foreach ($urls as &$url) {
    $u = parse_url($url);
    $url = "$u[scheme]://$domain$u[path]" . (isset($u["query"]) ? "?$u[query]" : "");
}
print_r($urls);

edited Sep 13, 2017 at 18:15

answered Mar 20, 2017 at 18:53

miken32

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1 Comment

supersan Over a year ago

this is the best answer.. never use regex when there is a native way to do it.

David Evdoschenko · Accepted Answer · 2019-12-07 09:48:39Z

5

Maybe it's too late... For a single string:

$components = parse_url( $url);
return str_replace($components['host'], 'anydomain.com', $url);

Protocol in url required. If urls are array - run above in a loop

answered Dec 7, 2019 at 9:48

David Evdoschenko

511 silver badge1 bronze badge

Comments

Hossam · Accepted Answer · 2017-03-16 17:24:39Z

2

use:

$new_string = preg_replace("/(http|https):\/\/(?:.*?)\/ups\//i", "$1://anydomain.com/ups/", $old_string);

so for input string:

http://subdomain.domain.com/ups/a/b.gif
https://www.domainX.com/ups/c/k.gif
http://subdomain1.domain.com/ups/l/k.docx

the output will be:

http://anydomain.com/ups/a/b.gif
https://anydomain.com/ups/c/k.gif
http://anydomain.com/ups/l/k.docx

edited Mar 16, 2017 at 17:24

answered Mar 16, 2017 at 17:09

Hossam

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3 Comments

Deepanshu Garg Over a year ago

Thanks @Hossam but it should also catch "/ups/" also. It should not work over "subdomain.domain.com/upss" while replace

Hossam Over a year ago

@DeepanshuGarg : updated the code to catch only url's with "/ups/" after the domain name

Hossam Over a year ago

You're welcome. You can mark the answer as right & upvote ^__^

Jonathan · Accepted Answer · 2017-03-16 17:20:45Z

You'll want to make use of regular expressions.

An explanation of what's going on with the regular expression:

# /^(http[s]?:\/\/).*?\/(.*)$/
# 
# / starting delimiter
# ^ match start of string
# (http[s]?:\/\) match http:// or https://
# .*? match all characters until the next matched character
# \/ match a / slash
# (.*) match the rest of the string
# 
# in the replacement
# 
# $1 = https:// or https://
# $2 = path on the url

$urls = [
    'https://subdomain.example.org/ups/a/b.gif',
    'http://www.example.org/ups/c/k.gif',
    'https://subdomain1.example.org/ups/l/k.docx'
];

foreach($urls as $key => $url) {
    $urls[$key] = preg_replace('/^(http[s]?:\/\/).*?\/ups\/(.*)$/', '$1anydomain.com/ups/$2', $url);
}

print_r($urls);

Result

Array
(
    [0] => https://anydomain.com/ups/a/b.gif
    [1] => http://anydomain.com/ups/c/k.gif
    [2] => https://anydomain.com/ups/l/k.docx
)

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