Get PHP variabile in div from ajax call [duplicate]

Question

I have this code in default.php:

jQuery(document).ready(function() {
  jQuery(function($) {
    var $from = jQuery("#from"),
      $to = jQuery("#to");

    $from.datepicker({
      numberOfMonths: 1,
      minDate: 1,
      dateFormat: 'dd-mm-yy',
      onClose: function(selectedDate) {
        $to.datepicker("option", "minDate", selectedDate);
      }
    });

    $from.change(function() {

      jQuery.ajax({
        url: 'index.php?option=com_vehiclemanager&task=default2',
        type: 'POST',
        data: {
          datepicker_value: $(this).val()
        },
        success: function(data) {
          $('#result').html(data);
        }
      });
    });

    ...

This is the php script:

<?php

$database = JFactory::getDBO();

$datepicker_value = isset($_POST['datepicker_value']) ? $_POST['datepicker_value'] : NULL;  
$month = date("m",strtotime($datepicker_value));

  $selectstring = "SELECT * FROM #__vehiclemanager_rent_sal WHERE fk_vehiclesid = 128 AND monthW = '$month'";
  $database->setQuery($selectstring);
  $string = $database->loadObject(); 


header('Content-Type: application/json');
$array[] = array(
'deposito'=>$string->deposit, 
'spese'=>$string->cfee,
);
echo json_encode($array);
?>

I have a jquery datepicker in a table and i want to pick the variable from the php script via a database query with an ajax call, i can see the json object [{"deposito":"300","spese":"100"}] but the single php variabile shows me undefined. I inserted the task in the ajax url because the filename sends me back to the index.php, the homepage, as this is an external plugin. I hope I explained myself and thanks for your help.

This is not necessary: jQuery(document).ready(function () { jQuery(function ($) { - THIS - $(function() {... is enough — mplungjan
– mplungjan, Commented Mar 30, 2017 at 16:51
@mplungjan Unless $ is overwritten by another library, it is effectively the same. — Xorifelse
– Xorifelse, Commented Mar 30, 2017 at 16:53
It is almost never and if it is, then the method is api.jquery.com/jquery.noconflict — mplungjan
– mplungjan, Commented Mar 30, 2017 at 16:53
$(this) reffers to the event, document ready. Do datepicker_value: [from, to] instead and remove $ from $from and $to, prepend var instead. — Xorifelse
– Xorifelse, Commented Mar 30, 2017 at 16:57
You need to use onSelect: function(dateText) { instead of $from.change and then you have the value in dateText — mplungjan
– mplungjan, Commented Mar 30, 2017 at 17:04

Kirill Simin · Accepted Answer · 2017-03-30 16:51:16Z

0

Instead of $(this).val(), try referencing the actual element. Something like this: $('#from').val().

answered Mar 30, 2017 at 16:51

Kirill Simin

3542 silver badges12 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Get PHP variabile in div from ajax call [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related