Index of multiple minimum elements in a list [duplicate]

Question

I want a list

a = [2,4,5,2]

to give

b = [0, 3]

I know how to do it for when there is only a single min element, but not multiple min elements. example:

b = a.index(min(a))

This will give me b = 0.

falsetru · Accepted Answer · 2017-04-01 09:17:05Z

11

Find the minimum value, then iterate the list with index using enumerate to find the minimum values:

>>> a = [2,4,5,2]
>>> min_value = min(a)
>>> [i for i, x in enumerate(a) if x == min_value]
[0, 3]

answered Apr 1, 2017 at 9:17

falsetru

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2 Comments

@McGrady, just voted.

Miriam Farber · Accepted Answer · 2017-04-01 09:17:47Z

4

You can do that using numpy in the following way:

import numpy as np
a = np.array([2,4,5,2])
np.where(a==a.min())

answered Apr 1, 2017 at 9:17

Miriam Farber

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