How to send a HTTP POST with Python 2.7

Question

I'm trying to send a HTTP POST request with Python. I can get it to work with 3.0, but I couldn't find a good example on 2.7.

hdr = {"content-type": "application/json"}
payload= ("<html><body><h1>Sorry it's not Friday yet</h1> </body></html>")
r = requests.post("http://my-url/api/Html", json={"HTML": payload})

with open ('c:/temp/a.pdf', 'wb') as f:
    b64str = json.loads(r.text)['BinaryData']  #base 64 string is in BinaryData attr
    binStr = binascii.a2b_base64(b64str)  #convert base64 string to binary
    f.write(binStr)

The api takes a json in this format:

{
  HTML : "a html string"
}

and returns a json in this format:

{
    BinaryData: 'base64 encoded string'      
}

fn. · Accepted Answer · 2017-04-12 20:25:15Z

7

In Python 2.x it should be like this

import json
import httplib

body =("<html><body><h1>Sorry it's not Friday yet</h1> </body></html>")
payload = {'HTML' : body}
hdr = {"content-type": "application/json"}

conn = httplib.HTTPConnection('my-url')
conn.request('POST', '/api/Html', json.dumps(payload), hdr)
response = conn.getresponse()
data = response.read() # same as r.text in 3.x

edited Apr 12, 2017 at 20:25

answered Apr 12, 2017 at 20:11

fn.

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Comments

Uri Goren · Accepted Answer · 2018-05-05 21:45:42Z

4

The standard way is with the urllib2 module

from urllib import urlencode
import urllib2
def http_post(url, data):
    post = urlencode(data)
    req = urllib2.Request(url, post)
    response = urllib2.urlopen(req)
    return response.read()

answered May 5, 2018 at 21:45

Uri Goren

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1 Comment

jdhildeb Over a year ago

For the data parameter, you'd typically pass a dict.

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