I want to know how for loop is processed in below condition.
void main()
{
int i,j;
For(i=1,j=1;i<=5,j<=10,i++,j++)
{
printf("%d%d",i,j);
}
}
sorry for typo mistake I correct my syntax here
For(i=1,j=1;i<=5,j<=10;i++,j++)
answer of this -1122334455667788991010
How's that possible because loop for I will be iterate for only 5 times how's that possible ? I want to know how loop will be executed ?
This won't compile, there's only one ; in the for which is a syntax error.
I'll assume it should read like this:
for(i=1, j=1; i<=5, j<=10; i++, j++)
then it would step both i and j to 10.
This is because the for-loop's middle part, the condition, reads i<=5,j<=10 which is a use of the comma operator where perhaps a boolean and (&&) would be better.
It will evaluate i<=5, throw away that result, and then evaluate j<=10, running the loop for as long as that value is non-zero.
#include <stdio.h>
int main(int argc, char** args){
for(int i = 0, j=0; i<10&&j<10; i++, j++){
printf("%d, %d\n", i, j);
}
}
The semi colon's seperate the terms of the for statement. (intializer; condition; action at end of loop) You can do what you like for the sections.
, and they didn't ask why how. I just pasted the correct syntax.