Get curl http code

Question

I have the following cURL request. I want to get the http_code, but I want in a different variable, because otherwise it messes with parsing the JSON response from the GET call.

Is there anyway to do this?

curl --write-out %{http_code} --silent --output GET --header "Accept: application/json" --header "URL"

anubhava · Accepted Answer · 2017-06-02 19:48:20Z

2

Just use command substitution to store status code in a variable:

status=$(curl --write-out %{http_code} --silent --output tmp.out GET --header "Accept: application/json" --header "URL")
data=$(<tmp.out)

# check status now
declare -p status

# check data
declare -p data

edited Jun 2, 2017 at 19:48

answered Jun 2, 2017 at 19:10

anubhava

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7 Comments

Nishant Roy Over a year ago

I also need the actual output though. Does this give me both the output and the status code?

Nishant Roy Over a year ago

This just appends the status code to the end of the JSON response.

anubhava Over a year ago

But you have --output /dev/null which is suppressing all the output.

Nishant Roy Over a year ago

My bad! That was a typo. Lemme edit that in the question. Any suggestions now?

Nishant Roy Over a year ago

@anubhava: This is what I see as output declare -- status="000<JSON_RESPONSE>200" declare -- data="" Not exactly what I wanted, but I think you're close?

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Always Learn · Accepted Answer · 2017-06-02 19:09:48Z

0

curl -i -H "Accept: application/json" "server:5050/a/c/getName{"param0":"Arvind "}"

answered Jun 2, 2017 at 19:09

Always Learn

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1 Comment

Nishant Roy Over a year ago

This is just functioning as a regular curl request.

Always Learn · Accepted Answer · 2017-06-02 19:17:14Z

0

curl -w 'RESP_CODE:%{response_code}' -s -X POST --data '{"asda":"asd"}' http://example.com --header "Content-Type:application/json"|grep -o 'RESP_CODE:[1-4][0-9][0-9]'

answered Jun 2, 2017 at 19:17

Always Learn

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Nishant Roy Over a year ago

I need both the response code AND the actual JSON response

Always Learn · Accepted Answer · 2017-06-02 19:22:28Z

0

response=$(curl -sb -H "Accept: application/json" "http://host:8080/some/resource") For response just try $response

answered Jun 2, 2017 at 19:22

Always Learn

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Always Learn · Accepted Answer · 2017-06-02 19:26:33Z

0

Try this following may be this could help you to find the solution https://gist.github.com/sgykfjsm/1dd9a8eee1f70a7068c9

answered Jun 2, 2017 at 19:26

Always Learn

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