I have a string of 9 space-separated integers, like "3 4 6 9 8 8 2 3 4", which I want to convert to a 3x3 int Array.
A simple solution is to do two loops over a new matrix and convert string values as I go. Is there a more elegant way to do this?
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You might want to specify where you want the rectangular array [,] or the jagged one [][].Dmitri Nesteruk– Dmitri Nesteruk2010-12-29 11:43:06 +00:00Commented Dec 29, 2010 at 11:43
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i want the array to be rectangular thanks Dmitriaristotaly– aristotaly2010-12-29 11:45:36 +00:00Commented Dec 29, 2010 at 11:45
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3 Answers
Using my Split extension from Split a collection into `n` parts with LINQ?
var nums = s.Split(' ').Select(n=>Int32.Parse(n)).ToList();
var grid = nums.Split(nums.Count / 3);
answered Dec 29, 2010 at 11:53
Muhammad Hasan Khan
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Basically, your solution is as good as you can go. You can accomplish the same thing with LINQ:
int[][] result =
s.Split(' ')
.Select((a, index) => new {index, value = int.Parse(a)})
.GroupBy(tuple => tuple.index / 3)
.Select(g => g.Select(tuple => tuple.value).ToArray())
.ToArray();
For this problem, the LINQ solution is probably worse than the normal solution; however, the idea may be helpful for similar problems.
Comments
You can do an split over the " " character string.split() and you will get an array of string with the numbers. Then you must cast them to integers and distribute a plain array to you desired array and as far as I know there is no way to do that in another way that iterating through the array, but you will need only 1 loop.
answered Dec 29, 2010 at 11:40
Ignacio Soler Garcia
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