Convert Scala Seq to Java List

Question

I am working in Java. I am calling a scala function which returns a Seq[String]. To convert it to java's List, I tried using scala.collection.JavaConverters's asJava. But this does not seem to work.

Answers on similar questions have suggested either using JavaConversions or WrapAsJava, both of which are deprecated.

Similar Question - Converting Scala seq<string> to Java List<string>

//someScalaFunc returns a Seq[String]
List<String> listA = someScalaFunc();

chengpohi · Accepted Answer · 2017-09-08 03:54:19Z

12

Since JavaConversions is deprecated, You can use JavaConverters for this:

List<String> listA = scala.collection.JavaConverters.seqAsJavaList(someScalaFunc())

edited Sep 8, 2017 at 3:54

answered Sep 8, 2017 at 2:44

chengpohi

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4 Comments

piyush aggarwal Over a year ago

This worked fine, but I tried to import it statically, but someScalaFunc() is a generic function. Is there a way to import it in a static fashion, and avoid using class name with the function call?

chengpohi Over a year ago

import import static scala.collection.JavaConverters.seqAsJavaList and use seqAsJavaList(someScalaFunc()), Isn't it enough?

piyush aggarwal Over a year ago

No, it gives this error - seqAsJavaList (Seq<A>) in javaconverters cannot be applied to Seq<java.lang.String> And I checked that generic functions cannot be imported in a static way, either full class name has to be used or their return value should be stored in an intermediate variable. In this case intermediate variable cannot be used to store the scala Seq.

Sergey Over a year ago

@piyushaggarwal try JavaConverters.<String>seqAsJavaList(someScalaFunc())

Sohum Sachdev · Accepted Answer · 2017-09-08 03:52:53Z

2

You can use a Java to Scala implicit converter by importing the following:

import scala.collection.JavaConversions._

answered Sep 8, 2017 at 3:52

Sohum Sachdev

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Comments

Sergey · Accepted Answer · 2017-09-08 08:17:52Z

0

import scala.collection.JavaConverters._

val scalaList = List("A", "B", "c")

scalaList.asJava

edited Sep 8, 2017 at 8:17

Sergey

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answered Sep 8, 2017 at 5:58

Learner

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