Batch file command line arguments

Question

It seems an '=' sign on an argument splits that argument into two. ie. if I have a batch file a.bat:

echo %1
echo %2

and call it using:

a 1=2

it will give as a result:

1
2

whereas I want it to give:

1=2 for the first argument.

If I put quotes around "1=2" it works however it keeps the quotes in %1.

Any idea how to get 1=2 into %1 ?

well half my comments disappeared below, why is that?

Arthur
– Arthur

2017-09-10 18:10:39 +00:00
Commented Sep 10, 2017 at 18:10 — Arthur
– Arthur, Commented Sep 10, 2017 at 18:10
because they were comments to a now deleted answer.

Stephan
– Stephan

2017-09-11 15:27:45 +00:00
Commented Sep 11, 2017 at 15:27 — Stephan
– Stephan, Commented Sep 11, 2017 at 15:27

SomethingDark · Accepted Answer · 2017-09-10 17:14:19Z

1

To remove the surrounding quotes from an argument, include a ~.

echo %~1

answered Sep 10, 2017 at 17:14

SomethingDark

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9 Comments

Arthur Over a year ago

the argument doesn't have quotes: argument 1 is 1=2, I want that to go into %1

SomethingDark Over a year ago

Yes, if you put "1=2" in quotes, it will work. The ~ will then remove the quotes so that %1 will hold the value 1=2 and not "1=2".

Arthur Over a year ago

No you're missing the point, the user will not call the batch file with quotes, the user will call it with 1=2. It is my job in the batch file to interpret that correctly.

Aacini Over a year ago

Use %* instead of %1

user6811411 Over a year ago

@Arthur It is documented, just read call /? or ss64.com/nt/syntax-args.html

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