How to get the values from multiple form in one post request using laravel?

Question

Ajax:

<script type="text/javascript">
    $(document).ready(function () {
        $('#finalSubmit').click(function() {


            var form1 = $('#priceform').serialize();
            var form2 = $('#formdescription').serialize();
            var form3 = $('#additionaldescription').serialize();
    //var form4 = new FormData($("#imagesform").get(0));
    //alert(form4);

            $.ajaxSetup({
                headers: { 'X-CSRF-TOKEN': 
                $('meta[name="_token"]').attr('content') }
            });

            $.ajax({
                url      :"{{url('/dbvalue')}}",
                type: 'POST',
                data: {form1: form1, form2: form2,form3: form3},
                dataType:'json',
                success:function(data){
                    alert(data);

                }

            });
        });
    });

</script>

This is my ajax code.Here I'm passing the values of four forms

Controller:

public function finalSubmit(Request $request)
{      

    var_dump($_POST);
    $var1 = $this->addPriceDetails1($request->form1);

    $var2 = $this->addProductDetails1($request->form2);
    $var3 = $this->addAdditionalInformation1($request->form3);
        //$var4 = $this->addImages($imagesform);//you dont't have 
    $imagesform
    return response()->json(["response"=>"success"]);
}

Eg. for function:

public function addPriceDetails1($request)
{

    $priceInfo = new priceInfo ;
    $priceInfo->id=$this->getpriceDetailsId();
    $priceInfo->SKUID=$request->input('skuid');
    echo($priceInfo->id);

     //return $request->all();
}

Also here when I'm trying to echo the values of $priceInfo->Id it echoes '0'.I don't know why

With this I'm getting FatalErrorException..call to member function input() on string

var_dump($_POST) gives me an array of forms values.

UPdate:

  public function getpriceDetailsId()
 {
  $id = mt_rand(1000000, 9999999);
  $id="PD".$id;
  $count=priceInfo::select('id')->where('id',$id)->count();
  if($count==0)
  {
    return $id;
  }
  else
  {
    $this->getpriceDetailsId();
  }
  }

here is my function for getpriceDetailsId().

Viet Nguyen · Accepted Answer · 2017-09-11 06:52:34Z

1

You get that error because your input query when you access as object when it is string, you can convert your query string to an array to access like so.

public function addPriceDetails1($request)
{
    parse_str($request, $input);
    $priceInfo = new priceInfo ;
    $priceInfo->id = $this->getpriceDetailsId();
    $priceInfo->SKUID = $input['skuid'];
    echo($priceInfo->id);
}

Hope this help

answered Sep 11, 2017 at 6:52

Viet Nguyen

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8 Comments

user8268872 Over a year ago

It works..But I'm not getting the value for $priceInfo->id

Viet Nguyen Over a year ago

Well, for this you need show me where the getpriceDetailsId() is? Is on same controller or other?

Viet Nguyen Over a year ago

Why you rand your ID? Is your ID is not int because I see you add string into it $id="PD".$id;?, and why you only return your $id when is 0 if($count==0)? I don't know why you write this function and its purpose ^^

user8268872 Over a year ago

yes..my ID is string..and I'm returning it when $count==0 bcz that id should not be repeated

Viet Nguyen Over a year ago

I don't know your system so I can't help you with your function because I don't know what is use for.

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