I have a set of strings that look like:
"user-123"
"user-498"
"user-9891"
I want to return a set of integers like this:
123
498
9891
I can do this:
val mySet = // ....
mySet.map(x => x.replace("user-").toInt)
But if the toInt parsing fails it will crash, what would be a safer way to do this?
To ignore failed strings:
mySet.flatMap(s => Try(s.replace("user-", "").toInt).toOption)
Use the isDigit()
Try("user-1234".toCharArray.filter(_.isDigit)
.foldLeft("")((a, b) => a + b).toInt)
.getOrElse(0)
You can use simple regular expression to only keep the numerical values.
Something like this:
val mySet = Seq("user-123","user-498","user-9891")
mySet.map(_.replaceAll("[^\\d]", ""))
You could check for strings that will successfully convert to an Int:
mySet.map(_.stripPrefix("user-")).collect { case x if x.forall(_.isDigit) => x.toInt }
