java regex help

Question

I have a string with the following format:

String str = "someString(anotherString)(lastString)";

I wanted to replace the lastString inside the last brackets, i.e new String should be

newStr = "someString(anotherString)(modified)";

I am using regex with "\$([^\\}]+)\$$" pattern.

But I am unable to change only the last content inside brackets. The above regex gives me the output:

"someString(modified)";

I just want to replace the content of the last brackets, any characters can appear infront of last bracket.

ANy help is appreciated.

What's the code you're using to replace it?

Eric
– Eric

2011-01-07 17:52:38 +00:00
Commented Jan 7, 2011 at 17:52 — Eric
– Eric, Commented Jan 7, 2011 at 17:52

krakover · Accepted Answer · 2011-01-07 18:21:08Z

2

I think you have a typo in your expression. Replace the curly brackets with a regular one, and I think it will be fine.

answered Jan 7, 2011 at 18:21

krakover

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Costi Ciudatu · Accepted Answer · 2011-01-07 18:11:52Z

1

yourString.replaceAll("(.+\\(.+\\)\\()[^\\}]+(\\)$)", "$1modified$2")

answered Jan 7, 2011 at 18:11

Costi Ciudatu

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Comments

Tim Pietzcker · Accepted Answer · 2011-01-07 18:21:17Z

0

String resultString = subjectString.replaceAll(
    "(?x)\\(  # match opening parenthesis\n" +
    "[^()]*   # match 0 or more characters except parentheses\n" +
    "\\)      # match closing parenthesis\n" +
    "$        # match the end of the string", "(modified)");

So far, this is not allowing for whitespace between the closing parenthesis and the end of the string. You might want to insert a \\s* before the $ if you need to handle that case, too.

answered Jan 7, 2011 at 18:21

Tim Pietzcker

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