I have a string in the following format, I only need to extract the /jspFolderTestSecondLast/jspFolderTestLast,
which is the second last seperated by /.
www.name.com/jspFolderTestOne/jspFolderTestTwo/jspFolderTestAndmanyMore/jspFolderTestSecondLast/jspFolderTestLast
/jspFolderTestSecondLast/jspFolderTestLast can be varied in length but always gonna be separated by secong last /.
Any help is appreciated.
Thanks
String s = "www.name.com/jspFolderTestOne/jspFolderTestTwo/jspFolderTestAndmanyMore/jspFolderTestSecondLast/jspFolderTestLast"
String[] parts = s.split("/");
String whatYouWant = parts[parts.length-2] +"/" + parts[parts.length-1]
You don't need any regexes for that, since you can just split the string on '/' and get two last array indexes. But here's the regex anyway:
^.+(/[^/]+)(/[^/]+)$
$1 contains the first and $2 contains the second block
String str = "www.name.com/jspFolderTestOne/jspFolderTestTwo/jspFolderTestAndmanyMore/jspFolderTestSecondLast/jspFolderTestLast";
String are[] = str.split("/");//may be you need to add escape here
//take last two parts
Pattern p = Pattern.compile(".*(/[^/]+/[^/]+)$");
Matcher m = p.matcher("a/b/c/d.txt");
if( m.matches() ) {
System.out.println(m.group(1));
}
this is the javascript version:
"www.name.com/jspFolderTestOne/jspFolderTestTwo/jspFolderTestAndmanyMore/jspFolderTestSecondLast/jspFolderTestLast".search(/\/[^\/]*\/[^\/]*$/)
or you can group them nicely:
(/(\/[^\/]*)(\/[^\/]*)$/)
