Remove duplicates from String using sql

using Jeff's DelimitedSplit8K from http://www.sqlservercentral.com/articles/Tally+Table/72993/

declare @value      varchar(100) = '10,10,20,30,40,20',
    @new_value  varchar(100)

select  @new_value = isnull(@new_value + ',', '')  + Item
from    DelimitedSplit8K(@value, ',')
group by Item
order by Item

select  @new_value

Did this long ago. This might need some modifications. But it generates output.

Try :

DECLARE @Data_String AS VARCHAR(1000), @Result as varchar(1000)=''
SET @Data_String = '10,10,20,30,40,20'
SET @Data_String = REPLACE(@Data_String,'|',',')

select @Data_String;

SELECT @Result=@Result+col+',' from(
    SELECT DISTINCT t.c.value('.','varchar(100)') col from(
        SELECT cast('<A>'+replace(@Data_String,',','</A><A>')+'</A>' as     xml)col1)data 
    cross apply col1.nodes('/A') as t(c))Data
SELECT LEFT(@Result,LEN(@Result)-1)

believing it stores integer number you can get them with creating a function first you need to split the values then have to use a distinct function as below

1st create a function like

CREATE FUNCTION [dbo].[idpGetSplitedString]
(
    @String varchar(8000), 
    @Delimiter char(1)
)
RETURNS 
@temptable TABLE 
(
    items varchar(8000)
)
AS
BEGIN
    declare @idx int        
    declare @slice varchar(8000)        

    select @idx = 1        
        if len(@String)<1 or @String is null  return        

    while @idx!= 0        
    begin        
        set @idx = charindex(@Delimiter,@String)        
        if @idx!=0        
            set @slice = left(@String,@idx - 1)        
        else        
            set @slice = @String        

        if(len(@slice)>0)   
            insert into @temptable(Items) values(rtrim(ltrim(@slice)))        

        set @String = right(@String,len(@String) - @idx)        
        if len(@String) = 0 break        
    end  

    RETURN 
END

then call the function like

select [dbo].idpGetSplitedString as Values