Python nearest value digits

Question

I would like to round values to the nearest 10 (0-4 = 0; 5-14 = 1; 15-24=2, etc.) I can get round to nearest 10, but I want to single digits for each range of numbers, as the example shows.

From -5 to 4 = 0, 5 to 14 = 1, 15 to 24 = 2 etc...

What I have tried...

int(math.ceil(x / 10.0)) * 10

This gives to nearest 10, but starts from 0 and gives to nearest 10 instead of single digit.

Any advice is helpful.

This can help: docs.python.org/2/library/functions.html#round — crazyGamer
– crazyGamer, Commented Oct 25, 2017 at 14:03
I does for me on python 2.7 and 3.5, so I'm curious exactly what you're getting? — Tom Dalton
– Tom Dalton, Commented Oct 25, 2017 at 14:15

Community · Accepted Answer · 2020-06-20 09:12:55Z

1

We can simply use:

int(round(float(x)/10))

From the documentation:

round(number[, ndigits])

Return the floating point value number rounded to ndigits digits after the decimal point. If ndigits is omitted, it defaults to zero. The result is a floating point number. Values are rounded to the closest multiple of 10 to the power minus ndigits; if two multiples are equally close, rounding is done away from 0 (so, for example, round(0.5) is 1.0 and round(-0.5) is -1.0).

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Oct 25, 2017 at 14:29

Joe Iddon

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1 Comment

SGhaleb Over a year ago

Thanks, I got it to work like this int(round(x, -1 ) / 10)

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