I would like to perform some action on sliced DataFrame with multiple slice indexes. The pattern is df.iloc[0:24] , df.iloc[24:48], df.iloc[48:72] and so on with step 24 as you get it. How I can iterate it without to set it manually every time. More like df.iloc[x:z] and each iteration x=0, z=24 and next iteration with 24 step, x will be 24 and z=48 and so on. Thanks in advance, Hristo.
2 Answers
for loop iteration
for i in range(0, len(df), 24):
slc = df.iloc[i : i + 24]
groupby
df.groupby(df.index // 24 * 24).apply(your_function)
1 Comment
n1tk
+ 1 for the for loop, just want to make a note: ‘slc’ is the sliced dataframe that jnclude the iterations, so all operations are performed to the ‘slc’
output it will give df with
for i in range(0,len(df)):
dfnew = df.iloc[i : i + 42]
i = i + 1
print(dfnew)
0 to 41 indices data 1 to 42 2 to 43 by skipping first entire row with limit 42 rows of data.
1 Comment
NoahVerner
Even though this wasn't the solution OP needed, I for sure did, thank you.
df.iloc[::24]This is a very basic indexing problem, you really should look up slice notation.