Javascript - Sum of few numbers in array with reduce() or some other built-in method

Question

So I was wondering, if there is a shorter or different way to get the sum of FEW numbers in an array, not the complete array. For example if i want to get the sum of first 3 numbers in array, I know I can go trough loop like this:

var arr=[1,2,3,4,5];
var sum=0;
for(var i=0; i<3;i++){
sum+= arr[i];
}
console.log(sum);

But I would like to know if you can somehow use reduce() method? Or even some other built-in method? I tried reduce like this,few times on my own, but it isn't working:

var arr= [1,2,3,4,5];
arr.reduce(function(total,amount,index){
total+=amount;
if(index===2){
return total;
}
});

Jonas Wilms · Accepted Answer · 2020-06-09 21:19:21Z

12

arr
 .slice(0,3) //get the range
 .reduce((a,b) => a + b)//sum up

Or without slice:

arr.reduce((a,b,i) => i < 3 ? a + b : a, 0);

edited Jun 9, 2020 at 21:19

answered Nov 19, 2017 at 20:32

Jonas Wilms

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Oleksandr Fedotov · Accepted Answer · 2017-11-19 20:34:40Z

1

As an example, if you want to skip element by index 2.

var arr = [1,2,3,4,5];
arr.reduce(function(total,amount,index){
    if(index === 2) {
       return total;
    }
    return total + amount;
});

In your case you forgot to return new total, when the index is not 2.

answered Nov 19, 2017 at 20:34

Oleksandr Fedotov

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Andy · Accepted Answer · 2017-11-19 20:42:48Z

1

A function that takes an array, and two numbers representing the element range. It slices the array, and returns the sum of the numbers in that range using reduce.

let arr= [1,2,3,4,5];

function getRangeSum(arr, from, to) {
  return arr.slice(from, to).reduce((p, c) => {
    return p + c;
  }, 0);
} 

console.log(getRangeSum(arr, 2, 4));

edited Nov 19, 2017 at 20:42

answered Nov 19, 2017 at 20:36

Andy

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