Get name of image using split

Question

I'm stuck, trying to get the name of image after uploaded it.

C:\work\assets\pic_items\06c1dd6b-5173-47b6-be09-f5c76866996d.PNG

I always get this result all I want is just the last 06c1dd6b-5173-47b6-be09-f5c76866996d.PNG

I use .split but it doesn't seems to work

picture_path = uploadedFiles[0].fd.z[z.length-1].split('.');

Possible duplicate of Get value of a string after a slash in JavaScript — Adeel Imran
– Adeel Imran, Commented Dec 27, 2017 at 20:21

Intervalia · Accepted Answer · 2017-12-27 20:18:26Z

0

Try this:

var filePath = 'C:\\work\\assets\\pic_items\\06c1dd6b-5173-47b6-be09-f5c76866996d.PNG';
var fileName = filePath.split('\\').pop();
console.log(fileName) // 06c1dd6b-5173-47b6-be09-f5c76866996d.PNG

This will break the path into parts and then use pop to grab the last entry in the array, which is the filename.

answered Dec 27, 2017 at 20:18

Intervalia

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Tom · Accepted Answer · 2017-12-27 20:08:08Z

0

If you have C:\work\assets\pic_items\06c1dd6b-5173-47b6-be09-f5c76866996d.PNG and want 06c1dd6b-5173-47b6-be09-f5c76866996d.PNG, try:

var fileParts = filePath.split('\\');
filename = fileParts[fileParts.length - 1];

answered Dec 27, 2017 at 20:08

Tom

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Phix · Accepted Answer · 2017-12-27 20:08:10Z

0

You'll have to escape the backslashes as they're escape characters themselves:

var str = 'C:\\work\\assets\\pic_items\\06c1dd6b-5173-47b6-be09-f5c76866996d.PNG';
var li = str.lastIndexOf('\\'); // last index of backslash
console.log(str.slice(li + 1)) // 06c1dd6b-5173-47b6-be09-f5c76866996d.PNG

answered Dec 27, 2017 at 20:08

Phix

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