I have the following list and dictionary:
list = [[1,2,2],[2,3,3],[3,4,4]
dict = {1:[], 2:[], 3:[]}
Let's say I wanted to append all values that proceed dict[keys] into their respective keys such that:
dict = {1:[2,2], 2:[3,3], 3:[4,4]}
I've attempted using multiple loops to accomplish this. However whenever I do that all values get searched and appended to each dict[key] simultaneously. Any help would be appreciated!
l = [[1,2,2],[2,3,3],[3,4,4]]
# last key wins
d = {sublist[0]:sublist[1:] for sublist in l}
print(d)
You construct the dictionary from your lists elements. Do not use list or dict as names, they shadow the built-ins.
sublist[0] is the first element, sublist[1:] are the rest of the elements of each item in l.
More about the syntax used here: PEP 274: Dict Comprehensions
Outputs:
{1: [2, 2], 2: [3, 3], 3: [4, 4]} # last key wins (no duplicates present)
If you need to merge as well, you can use:
# merging keys into values as list of sublists
l = [[2,2,2],[2,3,3],[3,4,4]]
d1 = {}
for sub in l:
# creates dict of { key: [ [int,...], [int,...] ], ... } for same keys
d1.setdefault(sub[0],[]).append(sub[1:])
or by flattening:
# merging keys into values as flattened list
d2 = {}
for sub in l:
# creates dict of { key: [ int,...,int,... ], ... } for same keys
d2.setdefault(sub[0],[]).extend(sub[1:])
Outputs:
{2: [[2, 2], [3, 3]], 3: [[4, 4]]} # merging keys into values as list of sublists
{2: [2, 2, 3, 3], 3: [4, 4]} # merging keys into values as flattened list
For merging I used dict.setdefault() you might want to take a peek at collections.defaultdict() which I get assured is better suited.