Adding elements from a list of lists into dictionary in Python

Question

I have a list where it consists of a list inside a list. The inner list contains two items with inner_list[0] is an identifier/key and inner_list[1] is the corresponding value. I would like to put them into a dictionary where values that shares the same key will be appended to the same key.

An example:

list = [['Jan', 'Jim'], ['Feb', 'Maggie'], ['Jan', 'Chris'], ['Sept', 'Joey'],..['key', 'value']]

The outcome I was looking for:

Jan = ['Jim', 'Chris']
Feb = ['Maggie']
Sept = ['Joey']

Any ideas I can do this elegantly in Python?

for the record, the inner type is effectively a tuple (and ut should be a tuple if it is up to you) — Elazar
– Elazar, Commented Jun 11, 2013 at 5:33

Ashwini Chaudhary · Accepted Answer · 2013-06-11 05:31:04Z

6

You can use collections.defaultdict here:

>>> from collections import defaultdict
>>> lis = [['Jan', 'Jim'], ['Feb', 'Maggie'], ['Jan', 'Chris'], ['Sept', 'Joey'],['key', 'value']]
>>> dic = defaultdict(list)
>>> for k, v in lis:
...     dic[k].append(v)

>>> dic['Jan']
['Jim', 'Chris']
>>> dic['Feb']
['Maggie']
>>> dic['Sept']
['Joey']

answered Jun 11, 2013 at 5:31

Ashwini Chaudhary

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Comments

Sanjit · Accepted Answer · 2013-06-11 06:47:57Z

0

you could use setdefault, so:

lis = [['Jan', 'Jim'], ['Feb', 'Maggie'], ['Jan', 'Chris'], 
       ['Sept', 'Joey'], ['key', 'value']]
dic = {}
for key, val in lis:
    dic.setdefault(key, []).append(val)

answered Jun 11, 2013 at 6:47

Sanjit

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