Check if a button is pressed and then check again

Question

I am rather new to android developing and can't figure out how to do a double check on a button press. I am working in Android Studio and am trying to create a little simple game and have the following: two buttons (button1 and button2)declared and instantiated in an onClick method. When button 1 is pressed a counter is incremented and a specific value is shown on the button from an array with the values 0, 10, 50, 100. This part works like a charm. What I can't do is create a working "tiebreaker rule" which should be something like:

if (button1 value == 100 and button2 value == 100) or this can be done with the counter if (counter1 == 3 && counter2 == 3)
tiebreaker();

this is what I need to do:

public void tiebreaker(){
if (button1 is pressed){
   button1.setText(String.valueOf("OK. One more!");
   if (button1 is pressed (again){
       resetCounters();
       goForPlayer1(); //distinct method
   } else if (button2 is pressed) {
       //set both values back to 100
       tiebreaker(); //calls itself in order to repeat until a button is pressed twice consecutivelly
} (else?)
if(button2 is presed){
//same code as above, just with the numbers 1 and 2 swapped
}
}

I have tried implementing this tiebreaker method in different ways, but with no final success. I tried with if(button1.isPressed()) as condintion, having a boolean turn true when the button is pressed and using it as a condition, using the values from the buttons with button.equals("100") or whatever should be written but nothing.

Also, I tried making the tiebreaker as a second onClick method and doing checks based on switch (View.getId()) but the problem here is that the method being view dependant (tiebreaker(View v)) I am not sure how to call it from a different method.

IMO the main issue is that if within another if or switch/case within another switch/case can't be used when it comes to button presses (I could be wrong, though), but I don't know of any other way to do this.

I hope I did not miss anything and managed to make myself clear. I appreciate any input in helping me solve this tiebreaker rule. Thank you

Fattie · Accepted Answer · 2018-05-18 20:04:50Z

2

it's probably something like this ...

whenButtonAIsPressed() {

    do some stuff
    possiblyRunTiebreakerMaterial()
}

whenButtonBIsPressed() {

    do some stuff
    possiblyRunTiebreakerMaterial()
}

Note that you always run possiblyRunTiebreakerMaterial() and you always run it at the end of doing all your other processing.

Here's the nature of your possiblyRunTiebreakerMaterial() function...

possiblyRunTiebreakerMaterial() {

    // there are some conditions, which mean you DO want
    // to run the tie breaker:
    do some processing, such as
    value of A = blah blah
    value of B = blah blah

    // now have a boolean, and figure it out
    boolean  shouldWeRunTheTieBreaker

    processing
    processing
    shouldWeRunTheTieBreaker = blah

    and now finally:
    is shouldWeRunTheTieBreaker == true { tiebreaker() }
}

and then have your tiebreaker() function.

What you're really looking for is a state machine, but don't worry about that for now.

The general "programming trick" you're looking for here is that you must do these things:

always do your processing
then, only afterwards,
in all cases, check IF you need to run the tiebreaker
run it if needed

That's the pattern.

edited May 18, 2018 at 20:04

answered Mar 2, 2018 at 12:12

Fattie

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1 Comment

Andy Gix Over a year ago

Thank you for the answer. The issue I have is not checking if the tiebreaker should be called or not, but the interior of the method itself. At the moment I have no other idea about what to write inside the tiebreaker in order for it to do what I described above.

Andy Gix · Accepted Answer · 2018-03-03 08:58:18Z

-1

Unfortunately, I don't have the rating to upvote. I managed to resolve the issue. Instead of a function, I created a boolean for tiebreaker and it looks something like:

if (p1 = 100 || p2 == 100)
   tiebreak = true;
if (p1 == 100 && tiebreaker){
   p1 == OK;
   tiebreaker = false;
} else //same thing for p2

edited Mar 3, 2018 at 8:58

answered Mar 2, 2018 at 12:56

Andy Gix

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