URLConnection Error - java.io.IOException: Server returned HTTP response code: 400 for URL

Question

I am trying to connect to a URL from a desktop app, and I get the error indicated in the Title of my question, but when I tried to connect to the same URL from servlet, all works fine. When I load the URL from browser, all works fine. I am using the same code in the servlet. The code was in a library, when it didn't work, I pulled the code out to a class in the current project, yet it didn't work.

The URL https://graph.facebook.com/me.

The Code fragment.

public static String post(String urlSpec, String data) throws Exception {
    URL url = new URL(urlSpec);
    URLConnection connection = url.openConnection();
    connection.setDoOutput(true);
    OutputStreamWriter writer = new OutputStreamWriter(connection.getOutputStream());
    writer.write(data);
    writer.flush();

    BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
    String line = "";
    StringBuilder builder = new StringBuilder();
    while((line = reader.readLine()) != null) {
        builder.append(line);
    }
    return builder.toString();
}

I'm a little bit confused here, is there something that is present is a servlet that is not a normal desktop app?

Thanks.

FULL STACK TRACE

Feb 8, 2011 9:54:14 AM com.trinisoftinc.jiraffe.objects.FacebookAlbum create
SEVERE: null
java.io.IOException: Server returned HTTP response code: 400 for URL: https://graph.facebook.com/me
        at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1313)
        at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(HttpsURLConnectionImpl.java:234)
        at com.jiraffe.helpers.Util.post(Util.java:49)
        at com.trinisoftinc.jiraffe.objects.FacebookAlbum.create(FacebookAlbum.java:211)
        at com.trinisoftinc.jiraffe.objects.FacebookAlbum.main(FacebookAlbum.java:261)

Community · Accepted Answer · 2017-05-23 12:26:14Z

51

EDIT: You need to find the exact error message that facebook is sending in the response You can modify your code to get the message from the error stream like so:

HttpURLConnection httpConn = (HttpURLConnection)connection;
InputStream is;
if (httpConn.getResponseCode() >= 400) {
    is = httpConn.getErrorStream();
} else {
    is = httpConn.getInputStream();
}

Take a look at how you are passing the user context Here's some information that could help you out:

Look at the error message behind the 400 response code:

"Facebook Platform" "invalid_request" "An active access token must be used to query information about the current user*

You'll find the solution here

HTTP/1.1 400 Bad Request
...
WWW-Authenticate: OAuth "Facebook Platform" "invalid_request" "An active access token must be used to query information about the current user."
...

edited May 23, 2017 at 12:26

CommunityBot

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answered Feb 8, 2011 at 9:08

Ryan Fernandes

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5 Comments

Akintayo Olusegun Over a year ago

I am passing the same token as I am passing in the Servlet. I am sure the token is correct coz I used it to load the URL on the browser. I appreciate your comment though. I am thinking maybe facebook treats Desktop and Web Apps requests differently, or something like that.

Ryan Fernandes Over a year ago

updated the answer; you should peek into the error stream to get the exact message sent to you by the facebook service

Pashok Over a year ago

@RyanFernandes it's should be the opposite: if (httpConn.getResponseCode() >= 400) { is = httpConn.getErrorStream(); } else { is = httpConn.getInputStream(); }

Will Madison Over a year ago

This is minor but it may be a bit "cleaner" to check like so: if (httpConn.getResponseCode >= HttpURLConnection.HTTP_BAD_REQUEST) Just a thought.

Steve Chambers Over a year ago

Updated the answer with the correct way round for error/input stream (see Pashok's previous comment).

Akintayo Olusegun · Accepted Answer · 2011-02-08 10:07:41Z

4

I finally found the problem. Of course it's my code. One part of the code I didn't post is the value of data. data must contain only name and description but I am passing more than name and description.

answered Feb 8, 2011 at 10:07

Akintayo Olusegun

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