I have a super simple PHP code that looks like
$location = 'spain';
if ($location != 'usa' || $location != 'spain') {
echo 'Not Spain';
} else {
echo 'This is Spain';
}
I am expecting it to echo 'This is Spain' but it is not, am I using the OR operator incorrectly?
No, you should be using AND here.
To understand why, replace the variable $location with the actual string 'spain':
if ('spain' != 'usa' || 'spain' != 'spain') {
echo 'Not Spain';
} else {
echo 'This is Spain';
}
You can plainly see that the first condition will be true, because "spain" is indeed not the same as "usa". That's why you're getting 'Not Spain' as a result.
Probably in this case you`d want to use AND operator
if ($location != 'usa' && $location != 'spain') {
echo 'Not Spain';
} else {
echo 'This is Spain';
}
No its your condition is wrong.
$location = 'spain';
if ($location == 'usa' || $location != 'spain') {
echo 'Not Spain';
} else {
echo 'This is Spain';
}
When you use or condition then it means if any condition is true then it happen so your $location !=' usa' return true because your location value not usa it's sapin
Your conditional expression logic has unnecessary redundancy. You are performing a full string comparison and to determine if a string is spain or not, you only need one condition. (USA's got nothing to do with the logic.)
$location = 'spain';
if ($location != 'spain') {
echo 'Not Spain';
} else {
echo 'This is Spain';
}
If you wish to determine if the string is spain or usa and output an accurate response, using == comparisons and add an elseif expression.
$location = 'spain';
if ($location == 'spain') {
echo 'This is Spain';
} elseif ($location == 'usa') {
echo 'This is USA';
} else {
echo 'This is neither Spain, nor USA';
}
if ($location == 'spain') { echo 'This is Spain'; } else { echo 'Not Spain';}