Rename files with given names in python

Question

[PYTHON] Hi everyone, I have a problem to solve. I have two folders like this

FOLDER 1:

05.xml
06.xml
07.xml
08.xml

FOLDER 2:

01_2500.jpeg
02_2501.jpeg
03_2502.jpeg
04_2503.jpeg
05_2504.jpeg
06_2505.jpeg
07_2506.jpeg
08_2507.jpeg

I need to rename the folder 1 as follows:

2504.xml
2505.xml
2506.xml
2507.xml

How can I do it? I have been trying this for days. Obviously this is a simplified example, because there are actually thousands of files to rename.

I thought that I could use split function for the folder 2 and then apply if, but I can't.

Ajax1234 · Accepted Answer · 2018-05-28 16:31:39Z

2

You can create a lookup from the files in folder 2, and then apply os.rename by iterating over the contents of folder 1. The dictionary created from files in folder store store the leading digit as its key, and the trailing four digit run as a value:

import os, re
renames = dict(re.findall('\d+', i) for i in os.listdir('/folder2'))
for i in os.listdir('/folder1'):
   os.rename(i, re.sub('\d+(?=\.xml)', lambda x:renames[x.group()], i)

edited May 28, 2018 at 16:31

answered May 28, 2018 at 16:13

Ajax1234

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