I would like to write a function in which the default value of one argument is a function of some arguments that are being passed to the same function. Something like this:
def function(x, y = function2(x)):
##definition of the function
Is it possible to write such a function in Python? I came across this answer for c++. But there is no method overloading in Python
Thanks in advance.
A pretty usual way of solving this is by using None as a placeholder:
def function(x, y=None):
if y is None:
y = f2(x)
pass # whatever function() needs to do
This makes no sense. hat are you trying to achieve? What is the Y? Is taht function? then you must write:
def function(x, y = function2):
##definition of the function
If the Y is a simple value then you must write:
def function(x, y = None):
if y is None:
y = function2(x)
I don't know what exactly are you trying to achieve here use case wise but you can use a decorator that does what is required for you.
A silly example is here https://repl.it/@SiddharthShishu/IntrepidPunctualProspect
def function(x, y=None):
if y is None:
y = f2(x)
