Python sort associative array with float values

Question

I have an associative array which I want to sort

  items = {1: [5, 30, 0.16666666666666666], 2: [10, 20, 0.5]}

I want to sort items by float value with descending order so after sorting I should get

 items = {2: [10, 20, 0.5], 1: [5, 30, 0.16666666666666666]}

Note I want to sort mainly these 0.16666666666666666 and 0.5

Any help is welcomed!

I don't understand your logic. Your list values are unchanged. But your keys are visually the other way round. Except internally [and for all intents] dictionaries are not considered ordered (unless you are using Python 3.7). — jpp
– jpp, Commented Jul 23, 2018 at 15:58

Maxime Chéramy · Accepted Answer · 2018-07-21 14:18:52Z

1

You need to create a new dict based on the sorted items of items:

items = {k: v for k, v in sorted(items.items(), reverse=True)}

Note that this will only work for Python 3.6+ for which the order is guaranteed to be the insertion order. I'd recommend using a list or an OrderedDict instead.

Example:

>>> items = {1: [5, 30, 0.16666666666666666], 2: [10, 20, 0.5]}
>>> items = {k: v for k, v in sorted(items.items(), reverse=True)}    
>>> items
{2: [10, 20, 0.5], 1: [5, 30, 0.16666666666666666]}

edited Jul 21, 2018 at 14:18

answered Jul 21, 2018 at 14:10

Maxime Chéramy

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2 Comments

Pradeep Rajvanshi Over a year ago

this solution is not working for this scenario {1: [60, 20, 3.0], 2: [100, 50, 2.0], 3: [120, 30, 4.0]} after {k: v for k, v in sorted(items.items(), reverse=True)} this is what I get {3: [120, 30, 4.0], 2: [100, 50, 2.0], 1: [60, 20, 3.0]}

Felk Over a year ago

try using a custom key for the call to sorted(): key=lambda item: item[1][-1], where the [1] means the value of the (key, value) tuple and [-1] accesses the last item of the array, which you said you want to sort by

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