I'm working on a simple project involving sockets. Kinda like telnet. I just want it to connect to port 80 and execute GET / Here is what I'm trying:
import socket
size = 100000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "localhost"
port = 80
s.connect((host, port))
stuff = "GET /"
s.send(stuff)
r = s.recv(size)
print(r)
The HTTP spec says that you need two newlines ('\r\n' * 2) after the header. Try:
stuff = 'GET /\r\n\r\n'
You need at least a blank line after the GET /, so use stuff = "GET /\n\n". Read this example.
your main problem is lacking a newline after "GET /". The HTTP protocol demands a newline, so the server is waiting for it, which is why you're waiting for a response.
(A minor problem is that your buffer size is too large, the Python socket module recommends a small power of 2 like 4096.)
I suggest:
import socket
size = 4096
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = "localhost"
port = 80
s.connect((host, port))
stuff = "GET /\n"
s.send(stuff)
buf = ''
while True:
r = s.recv(size)
if not r: break
buf += r
print(buf)
The loop at the end assures you'll get the entire response.
And finally, I recommend urllib2, which implements HTTP for you and avoids such bugs:
import urllib2
print(urllib2.urlopen('http://localhost').read())
GET / HTTP/1.1? RFC2616 seems to require the protocol version in the Request-Line