Getting date from a string without time in php

Question

I have to convert a string input to date "1990/07/22" to 22/07/1990 as date,My function is as follows as:

public function($date){
    $date_format_sec = strtotime($date);
    $date_of_birth = new \DateTime('@'.$date_format_sec);
}

It uploads date as 21/07/1990 since I didn't give time.How to get the exact date given as same as input.

You don't need to use strtotime($date) if $date is a valid date string, you can pass this on the constructor of DateTime and then format it to whatever you want. — Rafael
– Rafael, Commented Aug 16, 2018 at 8:20

Wimanicesir · Accepted Answer · 2018-08-16 08:06:37Z

2

You can format your date with php

$formatedDate = $date_of_birth->format('d-m-Y');

Documentation

answered Aug 16, 2018 at 8:06

Wimanicesir

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TsV · Accepted Answer · 2018-08-16 08:14:41Z

2

    $input = '1990/07/22';
    $date = \DateTime::createFromFormat('Y/m/d', $input)->format('d-m-Y');

answered Aug 16, 2018 at 8:14

TsV

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Rafael · Accepted Answer · 2018-08-16 08:23:33Z

1

As I said, you don't need to use strtotime, if the $date string is a valid date, the class DateTime will read it. After that you can use format.

In this example I set the format to be always the one you expect, while you can put any other format accepted by it.

public function getMyDate($date, $format = 'd/m/Y') {
    $date_of_birth = new \DateTime($date);

    return $date_of_birth->format($format);
}

answered Aug 16, 2018 at 8:23

Rafael

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Rahul DSouza · Accepted Answer · 2018-08-16 08:16:06Z

-2

    public function formatDate($date) {return date('d/m/Y', strtotime($date));}

answered Aug 16, 2018 at 8:16

Rahul DSouza

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2 Comments

Rafael Over a year ago

he's using a DateTime object... why would you go to strtotime if you have the object?

BDL Over a year ago

Although this code might (or might not) solve the problem, a good answer should always explain how the problem has been solved and what the code does.

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