Flask 404 error

Question

I am making a project using Flask. I am getting an error while running the app. Here is my code for python.

from flask import Flask,render_template

app = Flask(__name__)

app.route('/login')
app.route('/')
def login():
    return render_template('login.html')

if __name__ == '__main__':
    app.run(debug=True)

Here is the HTML page that I want to render.

{% extends 'base.html' %}


{% block title %}
Login | Websitename
{% endblock %}

{% block custom_styles %}

<style>
  div.card, .login{
    justify-content: center;
  }
</style>

{% endblock %}



{% block main_content %}
<div class="d-flex login">
<div class="card d-flex">
  <div class="card-body">

  <h3 class="card-header">Login</h3>
  <input type="text" name="email" placeholder="Email or Username">
  <input type="password" name="password" placeholder="Password">
  <button type="submit" name="button" class="btn btn-block btn-primary">LOGIN</button>

</div>
</div>
</div>

{% endblock %}

Here is the base.html code

<!DOCTYPE html>
<html lang="en"> 
<head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width,initial-scale=1.0">
    <link rel="stylesheet" href="{{ url_for('static',filename='bootstrap.min.css') }}">
    <title>{% block title %}{% endblock %}
    </title>
    {% block custom_styles %}{% endblock %}

 </head>
<body>

{% block main_content %}{% endblock %}


<script src="{{ url_for('static',filename='bootstrap.min.js') }}" charset="utf-8"></script>
<script src="{{ url_for('static',filename='jquery.min.js') }}" charset="utf-8"> 
   </script>
    <script src="{{ url_for('static',filename='popper.min.js') }}" charset="utf-8"> 
   </script></body></html>

I am using the PyCharm IDE. I copied the venv folder (only flask and other library files) from another flask project which is also using libraries used by this project. So is this ok to copy the venv folder's library files or I have to install all the libraries again for this project or other error in the code.

Thanks in advance...:)This is the error i am getting.

"So is this ok to copy the venv folder's library files" – copying virtualenvs is usually a bad idea, it's best to create a new one. — ash
– ash, Commented Aug 27, 2018 at 18:06
can you structure the app files and folders what you have been created. and there is also issue for @ over app — utks009
– utks009, Commented Aug 27, 2018 at 18:21

Mikhail Burshteyn · Accepted Answer · 2018-08-27 18:08:52Z

1

You're missing @ on your decorators. Your view function must be defined like this:

@app.route('/login')
@app.route('/')
def login():
    return render_template('login.html')

Otherwise the decorator is not applied to anything, so your function is not added as a view for your routes to your flask app.

You can read more about decorators in the PEP where they were introduced.

answered Aug 27, 2018 at 18:08

Mikhail Burshteyn

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Comments

Lingster · Accepted Answer · 2018-08-27 18:08:53Z

1

Your decorator looks incorrect:

app.route('/login')
app.route('/')
def login():
    return render_template('login.html')

try adding an @ character:

@app.route('/login')
@app.route('/')
def login():
    return render_template('login.html')

answered Aug 27, 2018 at 18:08

Lingster

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Comments

static const · Accepted Answer · 2018-08-27 18:07:41Z

0

from flask import Flask,render_template

app = Flask(__name__)


@app.route('/')

@app.route('/login/')
def login():
    return render_template('login.html')

if __name__ == '__main__':
    app.run(debug=True)

you're defining the function for '/' and not login. Let me know if this works

answered Aug 27, 2018 at 18:07

static const

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1 Comment

Ishaan Over a year ago

Sorry, this is an error while copying the code.I am defining for both ('/') and ('/login')

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