1

Saw some codes like below in a C++ project:

struct Foo{ 
    std::wstring x; 
    //blah
}

// this func returns a Foo object 

Foo getFoo(){ 
    //blah 
}

void main() { 
    Foo obj{getFoo()}; //why can initialize by another Foo object in {}? 
}

{} is list-initialization. But no Foo arguments are listed here. Why does this work? Does struct have default copy constructor?

And does Foo obj(getFoo()) work? Any difference from the way of using {}?

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  • 1. Foo has an implicitly declared copy constructor; 2. Foo obj(getFoo()) works too; 3. Same effect here. Commented Sep 13, 2018 at 1:23

1 Answer 1

Reset to default
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This is copy initialization. It calls the implicitly declared copy-constructor. Sources: https://en.cppreference.com/w/cpp/language/copy_initialization, https://en.cppreference.com/w/cpp/language/copy_constructor

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