How to generate random word from a set of characters in python

Question

I am looking to generate a random word list from a set of characters in python. Problem here:-

It is Generating like:- aaaaaa aaaaab aaaaac ...... So on

I want to add random function so it generate same length with randomization of alphabets it has like:- a15bef f45acd 9bbac0 ...... So on

Look With same length but random.

How to add random function to it?

#Code
import itertools

chrs = 'abcdef0123456789' # Change your required characters here
n = 6 # Change your word length here

for xs in itertools.product(chrs, repeat=n):
   print(''.join(xs))

please help me to solve it.

Raj - asked & answered here: stackoverflow.com/questions/2823316/… — keithpjolley
– keithpjolley, Commented Sep 16, 2018 at 11:37
Possible duplicate of stackoverflow.com/questions/2257441/… — Sruthi
– Sruthi, Commented Sep 16, 2018 at 11:39

Maxime Chéramy · Accepted Answer · 2018-09-16 11:50:21Z

3

itertools.product will generate all the possible values. Instead, what you want is to pick n random characters from chrs and concatenate them:

import random

chrs = 'abcdef0123456789' # Change your required characters here
n = 6 # Change your word length here

print(''.join(random.choices(chrs, k=5)))

answered Sep 16, 2018 at 11:50

Maxime Chéramy

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1 Comment

Raj Tekken Over a year ago

Very good suggested and its working without itertools and consume less memory means faster work.

Peyman.H · Accepted Answer · 2018-09-16 11:46:59Z

1

You can do it by random.choice:

import random
chrs = 'abcdef0123456789'
n = 6
result = ''.join(random.choice(chrs) for _ in range(n))

edited Sep 16, 2018 at 11:46

answered Sep 16, 2018 at 11:39

Peyman.H

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Comments

Alex · Accepted Answer · 2018-09-16 11:44:43Z

0

''.join(random.choice(‘abcdef0123456789’) for _ in range(N))

A cryptographical more secure option is here, below example will generate random string using all undercase alphabets and digits

''.join(random.SystemRandom().choice(string.ascii_uppercase + string.digits) for _ in range(N))

edited Sep 16, 2018 at 11:44

answered Sep 16, 2018 at 11:41

Alex

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2 Comments

Raj Tekken Over a year ago

it says - NameError: name 'string' is not defined

Alex Over a year ago

We import string, a module that contains sequences of common ASCII characters, and random, a module that deals with random generation

Pierre.Vriens · Accepted Answer · 2019-04-09 05:32:04Z

0

I use something like this

import random
def generateAWord (length):
    i = 0
    result = ""
    while i < length:
        letter = chr(33 + int(93 * random.random()))
        result += letter
        i +=1
    return result

33 in inside chr is the first ascii decimal that you want( 33 represent {!}). random.random() return the next random floating point number in the range [0.0, 1.0] so it times that 0.0 - 1.0 by 93 for example 0.1732*93 will result 16,1076 (and it cast that to int, so it will end as 16). So 93 represent the max result from the starting ascii decimal that you want(in this case 33) until the max ascii decimal that you want(in this case 33+93 is 126 which is {~} in ascii decimal).

Then chr will convert that result to char.

edited Apr 9, 2019 at 5:32

Pierre.Vriens

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answered Apr 9, 2019 at 4:07

Christophorus Reyhan

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