I would like to find words in a sentence starting with a prefix and remove the rest of the characters.
Example:
this sentence Type_123 contains a Type_uiy
I would like to remove the characters that come after Type so I can have:
this sentence Type contains a Type
I know how I would go to remove the prefix with regex str.replace(/Type_/g,'') but how do I do the opposite action?
N.B. js prior ES6 if possible
Use the expression \b(Type)\w+ to capture the Type prefix.
Explanation:
\b | Match a word boundary (beginning of word)
(Type) | Capture the word "Type"
\w+ | Match one or more word characters, including an underscore
var str = 'this sentence Type_123 contains a Type_uiy';
var regex = /\b(Type)\w+/g;
console.log(str.replace(regex, '$1'));The $1 in the replace() method is a reference to the captured characters. In this case, $1 stands for Type. So anywhere in the sentence, Type_xxx will be replaced with Type.
See MDN's documentation on the replace() method.
String.prototype.replace() method's documentation(from the Mozilla Developers Network would be better) will help, not only the OP, but anyone who sees your answer.
\b(Type)\w+ will replace Typer with Type, too. If you need to make sure there is an underscore, add it explicitly as in \b(Type)_\w+ , do not rely on \w.Install: https://github.com/icodeforlove/string-saw
let str = "Here's a sentence that contains Type_123 and Type_uiy";
let result = saw(str)
.remove(/(?<=Type_)\w+/g)
.toString();
The above would result in:
"Here's a sentence that contains Type_ and Type_"
str = str.replace(/\b(Type)_\w+/g,'$1')str.replace(/(?<=Type)\w+/g, '')