Create loop to find and replace in file, then create multiple output files

Question

I am new to coding and I have been looking for a way to write a loop that generates multiple files after changing one aspect of a master file.

I've used some examples to get started and can get the code working for changing and creating 1 file, but not the loop. Here's the code:

for i in 'seq 1 6'; do sed 's/ref.txt/ref${i}.txt/g' CPMIR.as > CPMIR${i}.as

In the end, I would like to change ref.txt in the CPMIR.as file to ref1.txt and output a new CPMIR1.as file, ref2.txt and output the CPMIR2.as, ref3.txt and output the CPMIR3.as,.... all the way to 6.

Thanks for your help!

See: Difference between single and double quotes in bash

Cyrus
– Cyrus

2018-10-17 02:57:26 +00:00
Commented Oct 17, 2018 at 2:57 — Cyrus
– Cyrus, Commented Oct 17, 2018 at 2:57
Please check: expand unix variable inside sed command

ashish_k
– ashish_k

2018-10-17 04:04:31 +00:00
Commented Oct 17, 2018 at 4:04 — ashish_k
– ashish_k, Commented Oct 17, 2018 at 4:04

potong · Accepted Answer · 2018-10-17 06:30:25Z

1

This might work for you (GNU sed & parallel):

seq 6 | parallel "sed 's/ref\.txt/ref'{}'.txt/g' CPMIR.as >CPMIR{}.as"

answered Oct 17, 2018 at 6:30

potong

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Comments

ashish_k · Accepted Answer · 2018-10-17 05:33:30Z

0

First of all, you haven't used backticks or better you should use $(..) for $(seq 1 6) ,also, you need to use double-quotes while using variables inside sed.

This should work:

#!/bin/bash

for i in $(seq 1 6)
do
sed "s/ref.txt/ref${i}.txt/" CPMIR.as > CPMIR${i}.as
done

edited Oct 17, 2018 at 5:33

answered Oct 17, 2018 at 3:53

ashish_k

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1 Comment

Cae.rich Over a year ago

Thanks @user123 I gave it a try, but the code isn't working on my end to create new file that only include the change of ref.txt to the corresponding ref$i.txt any thoughts what else I could try? Open to suggestions for other commands!

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