Python speech_recognition.UnknownValueError

Question

I'm trying to make a virtual assistant, right now it's suppost to just write down what I say. However when I try to test it it returns,

Traceback (most recent call last): File "/Users/danieldossantos/Desktop/jarvis/chats/main.py", line 14, in speech = r.recognize_google(audio, language = 'pt') File "/Library/Python/2.7/site-packages/speech_recognition/init.py", line 858, in recognize_google if not isinstance(actual_result, dict) or len(actual_result.get("alternative", [])) == 0: raise UnknownValueError() speech_recognition.UnknownValueError

I've checked my code and I haven't found any errors, at least not that I know of,

import speech_recognition as sr

r = sr.Recognizer()

with sr.Microphone() as s:
    r.adjust_for_ambient_noise(s)

    while True:
        audio = r.listen(s)

        speech = r.recognize_google(audio, language = 'pt')

        print('Você disse: ', speech)

you got any solution for this r.recognize_google(audio) ??? i got the same error too. — Ujwala Patil
– Ujwala Patil, Commented Feb 11, 2019 at 11:51

Ujwala Patil · Accepted Answer · 2019-02-13 03:48:35Z

1

yes, for me now its working. The problem was with audio ports, as most of our laptop have 2 ports :

1. audio out (Green colour)

2. microphone (pink colour)

You need to put your headphone jack in Audio out so that it can accept your speech as input.
As Your code is unable to get any input it returns error saying empty list []

get("alternative", [])) == 0.

answered Feb 13, 2019 at 3:48

Ujwala Patil

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Comments

marcin2x4 · Accepted Answer · 2021-04-10 18:09:46Z

0

import speech_recognition as sr
from os import walk

r = sr.Recognizer()
#optional
#r.energy_threshold = 300

def startConvertion(path = 'file.wav', lang = 'en-IN'): 
    with sr.AudioFile(path) as source:
        #print('Fetching File')
        audio_file = r.record(source)
        print(r.recognize_google(audio_file, language=lang))
startConvertion()

answered Apr 10, 2021 at 18:09

marcin2x4

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Comments

Akansha Sharma · Accepted Answer · 2024-04-12 15:44:26Z

0

This code works fine as well

r = sr.Recognizer()    
with sr.Microphone() as source:
    r.energy_threshold = 10000
    r.adjust_for_ambient_noise(source, 1.2)
    print("listening..")    
    audio = r.listen(source)    
    text = r.recognize_google(audio)        
    try:
        print(text)        
    except Exception as e:            
        print("Error" + str(e))

answered Apr 12, 2024 at 15:44

Akansha Sharma

1

1 Comment

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