Click on a link using selenium

Question

I'd like to click on the following link but it's not working:

<ul class="pagination pagination-large">
  <li style="display:inline;">
    <a name="Next" href="jamm/flavours/page=2" class="next">
      <span class="icon-navigate_next"></span>
    </a>
  </li> 
</ul>

My code

items = browser.find_elements_by_xpath("//ul[@class = 'pagination pagination-large']//li[@style ='display:inline;']")
print items
for k in items:
    print k
    k.click()
    print("clicked")
    k.send_keys(webdriver.common.keys.Keys.SPACE)

Accepted answer tells us that you haven't really tried everything as search by link @name/@class is the first thing you should have tried — Andersson
– Andersson, Commented Nov 6, 2018 at 9:15

Isma · Accepted Answer · 2018-11-06 09:08:20Z

1

I think the problem is the xpath you are using is not finding the element you need, in fact, it targets the list element, not the anchor.

Maybe you can try to identify the link by using the css class next instead:

items = browser.find_elements_by_class_name('next')
for item in items:
    item.click()

If it works now, you can either just use that if you don't have any other elements using it or you can fix your xpath.

edited Nov 6, 2018 at 9:08

answered Nov 6, 2018 at 9:05

Isma

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Comments

undetected Selenium · Accepted Answer · 2018-11-06 09:22:45Z

0

Try:

browser.find_elements_by_name('Next')

edited Nov 6, 2018 at 9:22

undetected Selenium

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answered Nov 6, 2018 at 8:41

H0axD3

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1 Comment

hellow Over a year ago

While this might answer the authors question, it lacks some explaining words and/or links to documentation. Raw code snippets are not very helpful without some phrases around them. You may also find how to write a good answer very helpful. Please edit your answer.

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