can anyone help me with this code. It must be done using for and if only.
0
1 0 1
2 1 0 1 2
3 2 1 0 1 2 3
4 3 2 1 0 1 2 3 4
I tired and think every stuff but I dont understand what i am missing. I am having a issue with generating 101, 21012, 3210123, 43211234
here is my code(which is wrong)
for i in range (1,6):
for t in range (i,5):
print('\t', end="")
for j in range (0,(2*i-1)):
print(2*i-1-j, "\t", end="")
print("")
If you allow list-comprehension
num = 4
for i in range(num+1):
j = [str(n) for n in range(i+1)]
k = list(reversed(j))
print (' '.join([' '] * (num-i) + k + j[1:]))
Output:
0
1 0 1
2 1 0 1 2
3 2 1 0 1 2 3
4 3 2 1 0 1 2 3 4
In each row, the numbers start high, then go down to zero, then go up again. Since loops typically only go in one direction, why not use two loops? If you have one loop count from i down to one and then the next one count from 0 up to i, you should get your desired result. Let me know if there's anything you would like for me to clarify about this.
so here is my final code which run correctly strong text
for i in range (1,6):
for t in range (i,5):
print('\t', end="")
for j in range (0,i):
print(i-j-1, "\t", end="")
for k in range (1,i):
print (k,"\t" ,end="")
print("")
\t in j and k print loop.This is a different solution using list:
n = 4
lizst = [0]
for h in range (1, n+2):
print("\t"*(n+1-h), end = "")
[print(e, "", end = "") for e in lizst]
lizst = [h] + lizst + [h]
print()
Soultion using just for loop.
spaces=4
limits=0
for line in range(5):
for space in range(spaces):
print(' ',end=' ')
for limit in range(limits,-1,-1):
print(limit,end=' ')
for limit in range(1,limits+1):
print(limit,end=' ')
spaces-=1
limits+=1
print('\n')
