python pyramid pattern print using for loop

Question

how do you manipulate the for loop to display an output just like

I tried coding like

n=6
for i in range(0,n):
    for j in range (n,0):
        print(j,end="")
print(i)

but it would print this

Shouldn't it print first the 5 in loop j first

Błotosmętek · Accepted Answer · 2017-07-02 21:08:01Z

3

Almost good, but to go down from n, range requires the third parameter - step - to be -1:

for i in range(n,0,-1):
    for j in range (n,i-1,-1):
        print(j,end="")
    print()

edited Jul 2, 2017 at 21:08

answered Jul 2, 2017 at 20:56

Błotosmętek

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2 Comments

Czar Luc Over a year ago

so i should replace the range in j to be (n,-1)?

Czar Luc Over a year ago

i just tried it and its good.Can you explain it how it works? I'm kind off confused on how it performs the code.

user94559 · Accepted Answer · 2017-07-02 21:10:50Z

2

A bunch of ways to solve this... here's one:

n = 5

for i in range(0, n):
    # Think of this range as "how many numbers to print on this line"
    for j in range(i + 1):
        # First number should be n, second n - 1, etc.
        print(n - j, end="")
    print() # newline before next i

(Note that I changed n to 5.)

answered Jul 2, 2017 at 21:10

user94559

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2 Comments

Czar Luc Over a year ago

I noticed you didn't put a second number in the j range. Why is it possible?

Chris Over a year ago

@CzarLuc Because the default value for the first argument is a zero.

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